(D^3-3D^2+4)y=0,y(0)=1,y(0)=-8,y(0)=-4

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Solution for (D^3-3D^2+4)y=0,y(0)=1,y(0)=-8,y(0)=-4 equation: 



(^3-3^2+4)D=0.D(0)=1.D(0)=-8.D(0)=-4

We move all terms to the left:

(^3-3^2+4)D-(0.D(0))=0

We add all the numbers together, and all the variables

(^3-3^2+4)D-0=0

We add all the numbers together, and all the variables

(^3-3^2+4)D=0

We multiply parentheses

D^2-3D^3+4D=0

We do not support eDpression: D^3

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